👆Ans. D
Explanation:
➡️ Here we have to select, i.e. it's a question of combination (and not permutation), as the order of the players do not matter. As the team must have at least 5 bowlers, two cases emerge:
➡️ Case I: Team has 5 bowlers and 6 batsmen. Number of ways of choosing such a team = Number of ways of choosing 5 bowlers out of 6 available and 6 batsmen out of 7 available = 6C5 × 7C6 = 6 × 7 = 42.
➡️ Case II: Team has 6 bowlers and 5 batsmen. Number of ways of choosing such a team = Number of ways of choosing 6 bowlers out of 6 available and 5 batsmen out of 7 available = 6C6 × 7C5 = 1 × 21 = 21.
➡️ Hence, total possible ways = 42 + 21 = 63.
Share & Join: @CSAT_2023
Explanation:
➡️ Here we have to select, i.e. it's a question of combination (and not permutation), as the order of the players do not matter. As the team must have at least 5 bowlers, two cases emerge:
➡️ Case I: Team has 5 bowlers and 6 batsmen. Number of ways of choosing such a team = Number of ways of choosing 5 bowlers out of 6 available and 6 batsmen out of 7 available = 6C5 × 7C6 = 6 × 7 = 42.
➡️ Case II: Team has 6 bowlers and 5 batsmen. Number of ways of choosing such a team = Number of ways of choosing 6 bowlers out of 6 available and 5 batsmen out of 7 available = 6C6 × 7C5 = 1 × 21 = 21.
➡️ Hence, total possible ways = 42 + 21 = 63.
Share & Join: @CSAT_2023
