πAns. D
Explanation:
β‘οΈ Here we have to select, i.e. it's a question of combination (and not permutation), as the order of the players do not matter. As the team must have at least 5 bowlers, two cases emerge:
β‘οΈ Case I: Team has 5 bowlers and 6 batsmen. Number of ways of choosing such a team = Number of ways of choosing 5 bowlers out of 6 available and 6 batsmen out of 7 available = 6C5 Γ 7C6 = 6 Γ 7 = 42.
β‘οΈ Case II: Team has 6 bowlers and 5 batsmen. Number of ways of choosing such a team = Number of ways of choosing 6 bowlers out of 6 available and 5 batsmen out of 7 available = 6C6 Γ 7C5 = 1 Γ 21 = 21.
β‘οΈ Hence, total possible ways = 42 + 21 = 63.
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Explanation:
β‘οΈ Here we have to select, i.e. it's a question of combination (and not permutation), as the order of the players do not matter. As the team must have at least 5 bowlers, two cases emerge:
β‘οΈ Case I: Team has 5 bowlers and 6 batsmen. Number of ways of choosing such a team = Number of ways of choosing 5 bowlers out of 6 available and 6 batsmen out of 7 available = 6C5 Γ 7C6 = 6 Γ 7 = 42.
β‘οΈ Case II: Team has 6 bowlers and 5 batsmen. Number of ways of choosing such a team = Number of ways of choosing 6 bowlers out of 6 available and 5 batsmen out of 7 available = 6C6 Γ 7C5 = 1 Γ 21 = 21.
β‘οΈ Hence, total possible ways = 42 + 21 = 63.
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